Saturday 8 February 2014

LOGARITHMS B19

Evaluate Log3(729 x 27).

Solution

= Log3(729 x 27)

= Log3729 +  Log327          (applying the product rule)

= Log336 +  Log333             ( 729= 36 and 27=33 by prime factorization)

= 6Log33 +  3Log33       ( remember  Logaac = cLogaa )

= (6 x 1) +  (3 x 1)          ( remember  Logaa = 1 )

= 6 + 3

= 9

Hence Log3(729 x 27) = 9


TRY THIS.................

Evaluate Log3(729 x 6561).



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