Friday 17 January 2014

LOGARITHMS B9

Evaluate Log2(4 x 16).

Solution

= Log2(4 x 16)

= Log24 +  Log216          (applying the product rule)

= Log222 +  Log224             ( 4= 22 and 16=24 )

= 2Log22 +  4Log22       ( remember  Logaac = cLogaa )

= (2 x 1) +  (4 x 1)          ( remember  Logaa = 1 )

= 2 + 4

= 6


hence Log2(4 x 16) = 6 

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