Wednesday 15 January 2014

LOGARITHMS B8

If log5(3x + 1)=3; find x

   Solution

log5(3x + 1)=3

 (3x + 1)=53      
                   
 3x + 1=125

3x =125 – 1

3x = 124

3x = 124   
3        3

X = 124/3


Hence x = 124/3

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