Tuesday 14 January 2014

LOGARITHMS B7


If log5(3x + 1)=2; find x

   Solution

log5(3x + 1)=2

 (3x + 1)=52      
                   
 3x + 1=25

3x =25 – 1

3x = 24

3x = 24   
3        3

X = 8


Hence x = 8

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