Monday 13 January 2014

FUNCTIONS B5




If F(x) = log2x, Find F(1/64)

Solution

F(x) = log2x

F(1/32) = log2(1/64)

F(1/32) = log264-1

F(1/32) = log2(26)-1

F(1/32) = log22(6 x -1)

F(1/32) = log22-6

F(1/32) = -6log22
F(1/32) = -6 x 1

F(1/32) = -6

Therefore F(1/32) = -6
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