CONGRUENCE OF SIMPLE POLYGONS B4

Prove that ∆ABC and ∆DCE are congruent in the following figure.

Solution

Given: figure ABCED.

Required to prove: ∆ABC and ∆DCE are congruent

Proof: AC = CD    (given)

<BAC = <CDE = 50⁰ (given)

<ACB = <DCE (opposite angles)

Hence ∆ACB ≡ ∆DCE by AAS rule (proved)