CONGRUENCE OF SIMPLE POLYGONS B10

If AB = CD and ABCD is a straight line, Prove that <BAF = <CDE

Solution

Given: figure ABEDCF.

Required to prove: <BAF and <CDE are equal.

Proof: AB= CD    (given)

EB= CF (equal sides)   

AF = ED (equal sides)

AB + BC = CD + BC  (equal sides)

Hence ∆ACF and ∆EBD by SSS rule

Therefore <BAF = <CDE Proved!