If Logb125 – log 0.00001 = 8; find b
Solution
Logb125 – log 0.00001 = 8; [0.00001=10-5
]
Logb125 – log 10-5 = 8
Logb125 – (-5log 10) = 8
Logb125 + 5log 10 = 8 [remember log 10 = 1]
Logb125 + (5 x 1) = 8
Logb125 + 5 = 8
Logb125 = 8 - 5
Logb125 = 3
[Change it into exponential notation]
125 = b3
53 = b3
b = 5
Hence b = 5
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