If
F(x) = log2x, Find F(1/32)
Solution
F(x)
= log2x
F(1/32)
= log2(1/32)
F(1/32)
= log232-1
F(1/32)
= log2(25)-1
F(1/32)
= log22(5 x -1)
F(1/32)
= log22-5
F(1/32)
= -5log22
F(1/32)
= -5 x 1
F(1/32)
= -5
Therefore F(1/32)
= -5
No comments:
Post a Comment