The sum of four consecutive numbers is 362. Find the 3rd number.
Solution
Let the numbers be as shown in the table below
1st number

2nd number

3rd number

4th number

TOTAL

n

n+1

n+2

n+3

362

Then, n + (n+1) + (n+2) + (n+3) = 362
4n + 1+2+3= 362
4n + 6 = 362
4n = 362 – 6
4n = 356
4n = 356
4 4
n = 89
3rd number = n +2
=
89 + 2
=
91
Hence the
3rd number is 91
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